AUTHORS:
This code is partly based on Sage code by David Kohel from 2005.
TESTS:
Pickling test:
sage: Q.<i,j,k> = QuaternionAlgebra(QQ,-5,-2)
sage: Q == loads(dumps(Q))
True
Bases: sage.structure.factory.UniqueFactory
There are three input formats:
EXAMPLES:
QuaternionAlgebra(a, b) - return quaternion algebra over the smallest field containing the nonzero elements a and b with generators i, j, k with \(i^2=a\), \(j^2=b\) and \(j \cdot i = -i \cdot j\):
sage: QuaternionAlgebra(-2,-3)
Quaternion Algebra (-2, -3) with base ring Rational Field
sage: QuaternionAlgebra(GF(5)(2), GF(5)(3))
Quaternion Algebra (2, 3) with base ring Finite Field of size 5
sage: QuaternionAlgebra(2, GF(5)(3))
Quaternion Algebra (2, 3) with base ring Finite Field of size 5
sage: QuaternionAlgebra(QQ[sqrt(2)](-1), -5)
Quaternion Algebra (-1, -5) with base ring Number Field in sqrt2 with defining polynomial x^2 - 2
sage: QuaternionAlgebra(sqrt(-1), sqrt(-3))
Quaternion Algebra (I, sqrt(-3)) with base ring Symbolic Ring
sage: QuaternionAlgebra(1r,1)
Quaternion Algebra (1, 1) with base ring Rational Field
Python ints, longs and floats may be passed to the QuaternionAlgebra(a, b) constructor, as may all pairs of nonzero elements of a ring not of characteristic 2. The following tests address the issues raised in trac ticket #10601:
sage: QuaternionAlgebra(1r,1)
Quaternion Algebra (1, 1) with base ring Rational Field
sage: QuaternionAlgebra(1,1.0r)
Quaternion Algebra (1.00000000000000, 1.00000000000000) with base ring Real Field with 53 bits of precision
sage: QuaternionAlgebra(0,0)
Traceback (most recent call last):
...
ValueError: a and b must be nonzero
sage: QuaternionAlgebra(GF(2)(1),1)
Traceback (most recent call last):
...
ValueError: a and b must be elements of a ring with characteristic not 2
sage: a = PermutationGroupElement([1,2,3])
sage: QuaternionAlgebra(a, a)
Traceback (most recent call last):
...
ValueError: a and b must be elements of a ring with characteristic not 2
QuaternionAlgebra(K, a, b) - return quaternion algebra over the field K with generators i, j, k with \(i^2=a\), \(j^2=b\) and \(i \cdot j = -j \cdot i\):
sage: QuaternionAlgebra(QQ, -7, -21)
Quaternion Algebra (-7, -21) with base ring Rational Field
sage: QuaternionAlgebra(QQ[sqrt(2)], -2,-3)
Quaternion Algebra (-2, -3) with base ring Number Field in sqrt2 with defining polynomial x^2 - 2
QuaternionAlgebra(D) - D is a squarefree integer; returns a rational quaternion algebra of discriminant D:
sage: QuaternionAlgebra(1)
Quaternion Algebra (-1, 1) with base ring Rational Field
sage: QuaternionAlgebra(2)
Quaternion Algebra (-1, -1) with base ring Rational Field
sage: QuaternionAlgebra(7)
Quaternion Algebra (-1, -7) with base ring Rational Field
sage: QuaternionAlgebra(2*3*5*7)
Quaternion Algebra (-22, 210) with base ring Rational Field
If the coefficients \(a\) and \(b\) in the definition of the quaternion algebra are not integral, then a slower generic type is used for arithmetic:
sage: type(QuaternionAlgebra(-1,-3).0)
<type 'sage.algebras.quatalg.quaternion_algebra_element.QuaternionAlgebraElement_rational_field'>
sage: type(QuaternionAlgebra(-1,-3/2).0)
<type 'sage.algebras.quatalg.quaternion_algebra_element.QuaternionAlgebraElement_generic'>
Make sure caching is sane:
sage: A = QuaternionAlgebra(2,3); A
Quaternion Algebra (2, 3) with base ring Rational Field
sage: B = QuaternionAlgebra(GF(5)(2),GF(5)(3)); B
Quaternion Algebra (2, 3) with base ring Finite Field of size 5
sage: A is QuaternionAlgebra(2,3)
True
sage: B is QuaternionAlgebra(GF(5)(2),GF(5)(3))
True
sage: Q = QuaternionAlgebra(2); Q
Quaternion Algebra (-1, -1) with base ring Rational Field
sage: Q is QuaternionAlgebra(QQ,-1,-1)
True
sage: Q is QuaternionAlgebra(-1,-1)
True
sage: Q.<ii,jj,kk> = QuaternionAlgebra(15); Q.variable_names()
('ii', 'jj', 'kk')
sage: QuaternionAlgebra(15).variable_names()
('i', 'j', 'k')
TESTS:
Verify that bug found when working on trac ticket #12006 involving coercing invariants into the base field is fixed:
sage: Q = QuaternionAlgebra(-1,-1); Q
Quaternion Algebra (-1, -1) with base ring Rational Field
sage: parent(Q._a)
Rational Field
sage: parent(Q._b)
Rational Field
Create a key that uniquely determines a quaternion algebra.
TESTS:
sage: QuaternionAlgebra.create_key(-1,-1)
(Rational Field, -1, -1, ('i', 'j', 'k'))
Create the object from the key (extra arguments are ignored). This is only called if the object was not found in the cache.
TESTS:
sage: QuaternionAlgebra.create_object("6.0", (QQ, -1, -1, ('i', 'j', 'k')))
Quaternion Algebra (-1, -1) with base ring Rational Field
Bases: sage.algebras.quatalg.quaternion_algebra.QuaternionAlgebra_abstract
The quaternion algebra of the form \((a, b/K)\), where \(i^2=a\), \(j^2 = b\), and \(j*i = -i*j\). K is a field not of characteristic 2 and a, b are nonzero elements of K.
See QuaternionAlgebra for many more examples.
INPUT:
EXAMPLES:
sage: QuaternionAlgebra(QQ, -7, -21) # indirect doctest
Quaternion Algebra (-7, -21) with base ring Rational Field
Given a quaternion algebra \(A\) defined over a number field, return the discriminant of \(A\), i.e. the product of the ramified primes of \(A\).
EXAMPLES:
sage: QuaternionAlgebra(210,-22).discriminant()
210
sage: QuaternionAlgebra(19).discriminant()
19
sage: F.<a> = NumberField(x^2-x-1)
sage: B.<i,j,k> = QuaternionAlgebra(F, 2*a,F(-1))
sage: B.discriminant()
Fractional ideal (2)
sage: QuaternionAlgebra(QQ[sqrt(2)],3,19).discriminant()
Fractional ideal (1)
Return the \(i^{th}\) generator of self.
INPUT:
EXAMPLES:
sage: Q.<ii,jj,kk> = QuaternionAlgebra(QQ,-1,-2); Q
Quaternion Algebra (-1, -2) with base ring Rational Field
sage: Q.gen(0)
ii
sage: Q.gen(1)
jj
sage: Q.gen(2)
kk
sage: Q.gens()
[ii, jj, kk]
Return the quaternion ideal with given gens over \(\ZZ\). Neither a left or right order structure need be specified.
INPUT:
EXAMPLES:
sage: R = QuaternionAlgebra(-11,-1)
sage: R.ideal([2*a for a in R.basis()])
Fractional ideal (2, 2*i, 2*j, 2*k)
Return the inner product matrix associated to self, i.e. the Gram matrix of the reduced norm as a quadratic form on self. The standard basis \(1\), \(i\), \(j\), \(k\) is orthogonal, so this matrix is just the diagonal matrix with diagonal entries \(1\), \(a\), \(b\), \(ab\).
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(-5,-19)
sage: Q.inner_product_matrix()
[ 2 0 0 0]
[ 0 10 0 0]
[ 0 0 38 0]
[ 0 0 0 190]
sage: R.<a,b> = QQ[]; Q.<i,j,k> = QuaternionAlgebra(Frac(R),a,b)
sage: Q.inner_product_matrix()
[ 2 0 0 0]
[ 0 -2*a 0 0]
[ 0 0 -2*b 0]
[ 0 0 0 2*a*b]
Return the structural invariants \(a\), \(b\) of this quaternion algebra: self is generated by \(i\), \(j\) subject to \(i^2 = a\), \(j^2 = b\) and \(j*i = -i*j\).
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(15)
sage: Q.invariants()
(-3, 5)
sage: i^2
-3
sage: j^2
5
Return a maximal order in this quaternion algebra.
The algorithm used is from [Voi2012].
INPUT:
OUTPUT:
A maximal order in this quaternion algebra.
EXAMPLES:
sage: QuaternionAlgebra(-1,-7).maximal_order()
Order of Quaternion Algebra (-1, -7) with base ring Rational Field with basis (1/2 + 1/2*j, 1/2*i + 1/2*k, j, k)
sage: QuaternionAlgebra(-1,-1).maximal_order().basis()
(1/2 + 1/2*i + 1/2*j + 1/2*k, i, j, k)
sage: QuaternionAlgebra(-1,-11).maximal_order().basis()
(1/2 + 1/2*j, 1/2*i + 1/2*k, j, k)
sage: QuaternionAlgebra(-1,-3).maximal_order().basis()
(1/2 + 1/2*j, 1/2*i + 1/2*k, j, k)
sage: QuaternionAlgebra(-3,-1).maximal_order().basis()
(1/2 + 1/2*i, 1/2*j - 1/2*k, i, -k)
sage: QuaternionAlgebra(-2,-5).maximal_order().basis()
(1/2 + 1/2*j + 1/2*k, 1/4*i + 1/2*j + 1/4*k, j, k)
sage: QuaternionAlgebra(-5,-2).maximal_order().basis()
(1/2 + 1/2*i - 1/2*k, 1/2*i + 1/4*j - 1/4*k, i, -k)
sage: QuaternionAlgebra(-17,-3).maximal_order().basis()
(1/2 + 1/2*j, 1/2*i + 1/2*k, -1/3*j - 1/3*k, k)
sage: QuaternionAlgebra(-3,-17).maximal_order().basis()
(1/2 + 1/2*i, 1/2*j - 1/2*k, -1/3*i + 1/3*k, -k)
sage: QuaternionAlgebra(-17*9,-3).maximal_order().basis()
(1, 1/3*i, 1/6*i + 1/2*j, 1/2 + 1/3*j + 1/18*k)
sage: QuaternionAlgebra(-2, -389).maximal_order().basis()
(1/2 + 1/2*j + 1/2*k, 1/4*i + 1/2*j + 1/4*k, j, k)
If you want bases containing 1, switch off take_shortcuts:
sage: QuaternionAlgebra(-3,-89).maximal_order(take_shortcuts=False)
Order of Quaternion Algebra (-3, -89) with base ring Rational Field with basis (1, 1/2 + 1/2*i, j, 1/2 + 1/6*i + 1/2*j + 1/6*k)
sage: QuaternionAlgebra(1,1).maximal_order(take_shortcuts=False) # Matrix ring
Order of Quaternion Algebra (1, 1) with base ring Rational Field with basis (1, 1/2 + 1/2*i, j, 1/2*j + 1/2*k)
sage: QuaternionAlgebra(-22,210).maximal_order(take_shortcuts=False)
Order of Quaternion Algebra (-22, 210) with base ring Rational Field with basis (1, i, 1/2*i + 1/2*j, 1/2 + 17/22*i + 1/44*k)
sage: for d in ( m for m in range(1, 750) if is_squarefree(m) ): # long time (3s)
....: A = QuaternionAlgebra(d)
....: R = A.maximal_order(take_shortcuts=False)
....: assert A.discriminant() == R.discriminant()
We don’t support number fields other than the rationals yet:
sage: K = QuadraticField(5)
sage: QuaternionAlgebra(K,-1,-1).maximal_order()
Traceback (most recent call last):
...
NotImplementedError: maximal order only implemented for rational quaternion algebras
REFERENCES:
| [Piz1980] | A. Pizer. An Algorithm for Computing Modular Forms on \(\Gamma_0(N)\), J. Algebra 64 (1980), 340-390. |
| [Voi2012] | J. Voight. Identifying the matrix ring: algorithms for quaternion algebras and quadratic forms, to appear. |
Return mod \(p\) splitting data for this quaternion algebra at the unramified prime \(p\). This is \(2\times 2\) matrices \(I\), \(J\), \(K\) over the finite field \(\GF{p}\) such that if the quaternion algebra has generators \(i, j, k\), then \(I^2 = i^2\), \(J^2 = j^2\), \(IJ=K\) and \(IJ=-JI\).
Note
Currently only implemented when \(p\) is odd and the base ring is \(\QQ\).
INPUT:
OUTPUT:
EXAMPLES:
sage: Q = QuaternionAlgebra(-15, -19)
sage: Q.modp_splitting_data(7)
(
[0 6] [6 1] [6 6]
[1 0], [1 1], [6 1]
)
sage: Q.modp_splitting_data(next_prime(10^5))
(
[ 0 99988] [97311 4] [99999 59623]
[ 1 0], [13334 2692], [97311 4]
)
sage: I,J,K = Q.modp_splitting_data(23)
sage: I
[0 8]
[1 0]
sage: I^2
[8 0]
[0 8]
sage: J
[19 2]
[17 4]
sage: J^2
[4 0]
[0 4]
sage: I*J == -J*I
True
sage: I*J == K
True
The following is a good test because of the asserts in the code:
sage: v = [Q.modp_splitting_data(p) for p in primes(20,1000)]
Proper error handling:
sage: Q.modp_splitting_data(5)
Traceback (most recent call last):
...
NotImplementedError: algorithm for computing local splittings not implemented in general (currently require the first invariant to be coprime to p)
sage: Q.modp_splitting_data(2)
Traceback (most recent call last):
...
NotImplementedError: p must be odd
Return Python map from the (\(p\)-integral) quaternion algebra to the set of \(2\times 2\) matrices over \(\GF{p}\).
INPUT:
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(-1, -7)
sage: f = Q.modp_splitting_map(13)
sage: a = 2+i-j+3*k; b = 7+2*i-4*j+k
sage: f(a*b)
[12 3]
[10 5]
sage: f(a)*f(b)
[12 3]
[10 5]
Return the order of this quaternion order with given basis.
INPUT:
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(-11,-1)
sage: Q.quaternion_order([1,i,j,k])
Order of Quaternion Algebra (-11, -1) with base ring Rational Field with basis (1, i, j, k)
We test out check=False:
sage: Q.quaternion_order([1,i,j,k], check=False)
Order of Quaternion Algebra (-11, -1) with base ring Rational Field with basis [1, i, j, k]
sage: Q.quaternion_order([i,j,k], check=False)
Order of Quaternion Algebra (-11, -1) with base ring Rational Field with basis [i, j, k]
Return the primes that ramify in this quaternion algebra. Currently only implemented over the rational numbers.
EXAMPLES:
sage: QuaternionAlgebra(QQ, -1, -1).ramified_primes()
[2]
Bases: sage.rings.ring.Algebra
Initialize self.
EXAMPLES:
sage: A = Algebra(ZZ); A
<type 'sage.rings.ring.Algebra'>
Return the fixed basis of self, which is \(1\), \(i\), \(j\), \(k\), where \(i\), \(j\), \(k\) are the generators of self.
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(QQ,-5,-2)
sage: Q.basis()
(1, i, j, k)
sage: Q.<xyz,abc,theta> = QuaternionAlgebra(GF(9,'a'),-5,-2)
sage: Q.basis()
(1, xyz, abc, theta)
The basis is cached:
sage: Q.basis() is Q.basis()
True
Return the inner product matrix associated to self, i.e. the Gram matrix of the reduced norm as a quadratic form on self. The standard basis \(1\), \(i\), \(j\), \(k\) is orthogonal, so this matrix is just the diagonal matrix with diagonal entries \(2\), \(2a\), \(2b\), \(2ab\).
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(-5,-19)
sage: Q.inner_product_matrix()
[ 2 0 0 0]
[ 0 10 0 0]
[ 0 0 38 0]
[ 0 0 0 190]
Return False always, since all quaternion algebras are noncommutative.
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(QQ, -3,-7)
sage: Q.is_commutative()
False
Return True if the quaternion algebra is a division algebra (i.e. every nonzero element in self is invertible), and False if the quaternion algebra is isomorphic to the 2x2 matrix algebra.
EXAMPLES:
sage: QuaternionAlgebra(QQ,-5,-2).is_division_algebra()
True
sage: QuaternionAlgebra(1).is_division_algebra()
False
sage: QuaternionAlgebra(2,9).is_division_algebra()
False
sage: QuaternionAlgebra(RR(2.),1).is_division_algebra()
Traceback (most recent call last):
...
NotImplementedError: base field must be rational numbers
Return True if elements of this quaternion algebra are represented exactly, i.e. there is no precision loss when doing arithmetic. A quaternion algebra is exact if and only if its base field is exact.
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(QQ, -3, -7)
sage: Q.is_exact()
True
sage: Q.<i,j,k> = QuaternionAlgebra(Qp(7), -3, -7)
sage: Q.is_exact()
False
Return False always, since all quaternion algebras are noncommutative and all fields are commutative.
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(QQ, -3, -7)
sage: Q.is_field()
False
Return True if the quaternion algebra is finite as a set.
Algorithm: A quaternion algebra is finite if and only if the base field is finite.
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(QQ, -3, -7)
sage: Q.is_finite()
False
sage: Q.<i,j,k> = QuaternionAlgebra(GF(5), -3, -7)
sage: Q.is_finite()
True
Return False always, since all quaternion algebras are noncommutative and integral domains are commutative (in Sage).
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(QQ, -3, -7)
sage: Q.is_integral_domain()
False
Return True if the quaternion algebra is isomorphic to the 2x2 matrix ring, and False if self is a division algebra (i.e. every nonzero element in self is invertible).
EXAMPLES:
sage: QuaternionAlgebra(QQ,-5,-2).is_matrix_ring()
False
sage: QuaternionAlgebra(1).is_matrix_ring()
True
sage: QuaternionAlgebra(2,9).is_matrix_ring()
True
sage: QuaternionAlgebra(RR(2.),1).is_matrix_ring()
Traceback (most recent call last):
...
NotImplementedError: base field must be rational numbers
Return True always, since any quaternion algebra is a noetherian ring (because it is a finitely generated module over a field).
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(QQ, -3, -7)
sage: Q.is_noetherian()
True
Return the number of generators of the quaternion algebra as a K-vector space, not including 1. This value is always 3: the algebra is spanned by the standard basis \(1\), \(i\), \(j\), \(k\).
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(QQ,-5,-2)
sage: Q.ngens()
3
sage: Q.gens()
[i, j, k]
Return the number of elements of the quaternion algebra, or +Infinity if the algebra is not finite.
EXAMPLES:
sage: Q.<i,j,k> = QuaternionAlgebra(QQ, -3, -7)
sage: Q.order()
+Infinity
sage: Q.<i,j,k> = QuaternionAlgebra(GF(5), -3, -7)
sage: Q.order()
625
Return a random element of this quaternion algebra.
The args and kwds are passed to the random_element method of the base ring.
EXAMPLES:
sage: QuaternionAlgebra(QQ[sqrt(2)],-3,7).random_element()
(sqrt2 + 2)*i + (-12*sqrt2 - 2)*j + (-sqrt2 + 1)*k
sage: QuaternionAlgebra(-3,19).random_element()
-1 + 2*i - j - 6/5*k
sage: QuaternionAlgebra(GF(17)(2),3).random_element()
14 + 10*i + 4*j + 7*k
Specify the numerator and denominator bounds:
sage: QuaternionAlgebra(-3,19).random_element(10^6,10^6)
-979933/553629 + 255525/657688*i - 3511/6929*j - 700105/258683*k
Return the vector space associated to self with inner product given by the reduced norm.
EXAMPLES:
sage: QuaternionAlgebra(-3,19).vector_space()
Ambient quadratic space of dimension 4 over Rational Field
Inner product matrix:
[ 2 0 0 0]
[ 0 6 0 0]
[ 0 0 -38 0]
[ 0 0 0 -114]
Bases: sage.rings.ideal.Ideal_fractional
Initialize this ideal.
INPUT:
EXAMPLES:
sage: R, x = PolynomialRing(ZZ, 'x').objgen()
sage: I = R.ideal([4 + 3*x + x^2, 1 + x^2])
sage: I
Ideal (x^2 + 3*x + 4, x^2 + 1) of Univariate Polynomial Ring in x over Integer Ring
Bases: sage.algebras.quatalg.quaternion_algebra.QuaternionFractionalIdeal
A fractional ideal in a rational quaternion algebra.
INPUT:
Return basis for this fractional ideal. The basis is in Hermite form.
OUTPUT: tuple
EXAMPLES:
sage: QuaternionAlgebra(-11,-1).maximal_order().unit_ideal().basis()
(1/2 + 1/2*i, 1/2*j - 1/2*k, i, -k)
Return basis matrix \(M\) in Hermite normal form for self as a matrix with rational entries.
If \(Q\) is the ambient quaternion algebra, then the \(\ZZ\)-span of the rows of \(M\) viewed as linear combinations of Q.basis() = \([1,i,j,k]\) is the fractional ideal self. Also, M * M.denominator() is an integer matrix in Hermite normal form.
OUTPUT: matrix over \(\QQ\)
EXAMPLES:
sage: QuaternionAlgebra(-11,-1).maximal_order().unit_ideal().basis_matrix()
[ 1/2 1/2 0 0]
[ 0 0 1/2 -1/2]
[ 0 1 0 0]
[ 0 0 0 -1]
Return the ideal with generators the conjugates of the generators for self.
OUTPUT: a quaternionic fractional ideal
EXAMPLES:
sage: I = BrandtModule(3,5).right_ideals()[1]; I
Fractional ideal (2 + 6*j + 4*k, 2*i + 4*j + 34*k, 8*j + 32*k, 40*k)
sage: I.conjugate()
Fractional ideal (2 + 2*j + 28*k, 2*i + 4*j + 34*k, 8*j + 32*k, 40*k)
Let \(I\) = self. This function returns the right subideals \(J\) of \(I\) such that \(I/J\) is an \(\GF{p}\)-vector space of dimension 2.
INPUT:
OUTPUT:
Note
Currently, \(p\) must satisfy a bunch of conditions, or a NotImplementedError is raised. In particular, \(p\) must be odd and unramified in the quaternion algebra, must be coprime to the index of the right order in the maximal order, and also coprime to the normal of self. (The Brandt modules code has a more general algorithm in some cases.)
EXAMPLES:
sage: B = BrandtModule(2,37); I = B.right_ideals()[0]
sage: I.cyclic_right_subideals(3)
[Fractional ideal (2 + 2*i + 10*j + 90*k, 4*i + 4*j + 152*k, 12*j + 132*k, 444*k), Fractional ideal (2 + 2*i + 2*j + 150*k, 4*i + 8*j + 196*k, 12*j + 132*k, 444*k), Fractional ideal (2 + 2*i + 6*j + 194*k, 4*i + 8*j + 344*k, 12*j + 132*k, 444*k), Fractional ideal (2 + 2*i + 6*j + 46*k, 4*i + 4*j + 4*k, 12*j + 132*k, 444*k)]
sage: B = BrandtModule(5,389); I = B.right_ideals()[0]
sage: C = I.cyclic_right_subideals(3); C
[Fractional ideal (2 + 10*j + 546*k, i + 6*j + 133*k, 12*j + 3456*k, 4668*k), Fractional ideal (2 + 2*j + 2910*k, i + 6*j + 3245*k, 12*j + 3456*k, 4668*k), Fractional ideal (2 + i + 2295*k, 3*i + 2*j + 3571*k, 4*j + 2708*k, 4668*k), Fractional ideal (2 + 2*i + 2*j + 4388*k, 3*i + 2*j + 2015*k, 4*j + 4264*k, 4668*k)]
sage: [(I.free_module()/J.free_module()).invariants() for J in C]
[(3, 3), (3, 3), (3, 3), (3, 3)]
sage: I.scale(3).cyclic_right_subideals(3)
[Fractional ideal (6 + 30*j + 1638*k, 3*i + 18*j + 399*k, 36*j + 10368*k, 14004*k), Fractional ideal (6 + 6*j + 8730*k, 3*i + 18*j + 9735*k, 36*j + 10368*k, 14004*k), Fractional ideal (6 + 3*i + 6885*k, 9*i + 6*j + 10713*k, 12*j + 8124*k, 14004*k), Fractional ideal (6 + 6*i + 6*j + 13164*k, 9*i + 6*j + 6045*k, 12*j + 12792*k, 14004*k)]
sage: C = I.scale(1/9).cyclic_right_subideals(3); C
[Fractional ideal (2/9 + 10/9*j + 182/3*k, 1/9*i + 2/3*j + 133/9*k, 4/3*j + 384*k, 1556/3*k), Fractional ideal (2/9 + 2/9*j + 970/3*k, 1/9*i + 2/3*j + 3245/9*k, 4/3*j + 384*k, 1556/3*k), Fractional ideal (2/9 + 1/9*i + 255*k, 1/3*i + 2/9*j + 3571/9*k, 4/9*j + 2708/9*k, 1556/3*k), Fractional ideal (2/9 + 2/9*i + 2/9*j + 4388/9*k, 1/3*i + 2/9*j + 2015/9*k, 4/9*j + 4264/9*k, 1556/3*k)]
sage: [(I.scale(1/9).free_module()/J.free_module()).invariants() for J in C]
[(3, 3), (3, 3), (3, 3), (3, 3)]
sage: Q.<i,j,k> = QuaternionAlgebra(-2,-5)
sage: I = Q.ideal([Q(1),i,j,k])
sage: I.cyclic_right_subideals(3)
[Fractional ideal (1 + 2*j, i + k, 3*j, 3*k), Fractional ideal (1 + j, i + 2*k, 3*j, 3*k), Fractional ideal (1 + 2*i, 3*i, j + 2*k, 3*k), Fractional ideal (1 + i, 3*i, j + k, 3*k)]
The general algorithm is not yet implemented here:
sage: I.cyclic_right_subideals(3)[0].cyclic_right_subideals(3)
Traceback (most recent call last):
...
NotImplementedError: general algorithm not implemented (The given basis vectors must be linearly independent.)
Return the underlying free \(\ZZ\)-module corresponding to this ideal.
EXAMPLES:
sage: X = BrandtModule(3,5).right_ideals()
sage: X[0]
Fractional ideal (2 + 2*j + 8*k, 2*i + 18*k, 4*j + 16*k, 20*k)
sage: X[0].free_module()
Free module of degree 4 and rank 4 over Integer Ring
Echelon basis matrix:
[ 2 0 2 8]
[ 0 2 0 18]
[ 0 0 4 16]
[ 0 0 0 20]
sage: X[0].scale(1/7).free_module()
Free module of degree 4 and rank 4 over Integer Ring
Echelon basis matrix:
[ 2/7 0 2/7 8/7]
[ 0 2/7 0 18/7]
[ 0 0 4/7 16/7]
[ 0 0 0 20/7]
The free module method is also useful since it allows for checking if one ideal is contained in another, computing quotients \(I/J\), etc.:
sage: X = BrandtModule(3,17).right_ideals()
sage: I = X[0].intersection(X[2]); I
Fractional ideal (2 + 2*j + 164*k, 2*i + 4*j + 46*k, 16*j + 224*k, 272*k)
sage: I.free_module().is_submodule(X[3].free_module())
False
sage: I.free_module().is_submodule(X[1].free_module())
True
sage: X[0].free_module() / I.free_module()
Finitely generated module V/W over Integer Ring with invariants (4, 4)
Return the generators for this ideal, which are the same as the \(\ZZ\)-basis for this ideal.
EXAMPLES:
sage: QuaternionAlgebra(-11,-1).maximal_order().unit_ideal().gens()
(1/2 + 1/2*i, 1/2*j - 1/2*k, i, -k)
Return the Gram matrix of this fractional ideal.
OUTPUT: \(4 \times 4\) matrix over \(\QQ\).
EXAMPLES:
sage: I = BrandtModule(3,5).right_ideals()[1]; I
Fractional ideal (2 + 6*j + 4*k, 2*i + 4*j + 34*k, 8*j + 32*k, 40*k)
sage: I.gram_matrix()
[ 640 1920 2112 1920]
[ 1920 14080 13440 16320]
[ 2112 13440 13056 15360]
[ 1920 16320 15360 19200]
Return the intersection of the ideals self and \(J\).
EXAMPLES:
sage: X = BrandtModule(3,5).right_ideals()
sage: I = X[0].intersection(X[1]); I
Fractional ideal (2 + 6*j + 4*k, 2*i + 4*j + 34*k, 8*j + 32*k, 40*k)
Return True if I and J are equivalent as right ideals.
INPUT:
OUTPUT: bool
EXAMPLES:
sage: R = BrandtModule(3,5).right_ideals(); len(R)
2
sage: R[0].is_equivalent(R[1])
False
sage: R[0].is_equivalent(R[0])
True
sage: OO = R[0].quaternion_order()
sage: S = OO.right_ideal([3*a for a in R[0].basis()])
sage: R[0].is_equivalent(S)
True
Return the left order associated to this fractional ideal.
OUTPUT: an order in a quaternion algebra
EXAMPLES:
sage: B = BrandtModule(11)
sage: R = B.maximal_order()
sage: I = R.unit_ideal()
sage: I.left_order()
Order of Quaternion Algebra (-1, -11) with base ring Rational Field with basis (1/2 + 1/2*j, 1/2*i + 1/2*k, j, k)
We do a consistency check:
sage: B = BrandtModule(11,19); R = B.right_ideals()
sage: print [r.left_order().discriminant() for r in R]
[209, 209, 209, 209, 209, 209, 209, 209, 209, 209, 209, 209, 209, 209, 209, 209, 209, 209]
Return product of self and the conjugate Jbar of \(J\).
INPUT:
OUTPUT: a quaternionic fractional ideal.
EXAMPLES:
sage: R = BrandtModule(3,5).right_ideals()
sage: R[0].multiply_by_conjugate(R[1])
Fractional ideal (8 + 8*j + 112*k, 8*i + 16*j + 136*k, 32*j + 128*k, 160*k)
sage: R[0]*R[1].conjugate()
Fractional ideal (8 + 8*j + 112*k, 8*i + 16*j + 136*k, 32*j + 128*k, 160*k)
Return the reduced norm of this fractional ideal.
OUTPUT: rational number
EXAMPLES:
sage: M = BrandtModule(37)
sage: C = M.right_ideals()
sage: [I.norm() for I in C]
[16, 32, 32]
sage: (a,b) = M.quaternion_algebra().invariants() # optional - magma
sage: magma.eval('A<i,j,k> := QuaternionAlgebra<Rationals() | %s, %s>' % (a,b)) # optional - magma
''
sage: magma.eval('O := QuaternionOrder(%s)' % str(list(C[0].right_order().basis()))) # optional - magma
''
sage: [ magma('rideal<O | %s>' % str(list(I.basis()))).Norm() for I in C] # optional - magma
[16, 32, 32]
sage: A.<i,j,k> = QuaternionAlgebra(-1,-1)
sage: R = A.ideal([i,j,k,1/2 + 1/2*i + 1/2*j + 1/2*k]) # this is actually an order, so has reduced norm 1
sage: R.norm()
1
sage: [ J.norm() for J in R.cyclic_right_subideals(3) ] # enumerate maximal right R-ideals of reduced norm 3, verify their norms
[3, 3, 3, 3]
Return the normalized quadratic form associated to this quaternion ideal.
OUTPUT: quadratic form
EXAMPLES:
sage: I = BrandtModule(11).right_ideals()[1]
sage: Q = I.quadratic_form(); Q
Quadratic form in 4 variables over Rational Field with coefficients:
[ 18 22 33 22 ]
[ * 7 22 11 ]
[ * * 22 0 ]
[ * * * 22 ]
sage: Q.theta_series(10)
1 + 12*q^2 + 12*q^3 + 12*q^4 + 12*q^5 + 24*q^6 + 24*q^7 + 36*q^8 + 36*q^9 + O(q^10)
sage: I.theta_series(10)
1 + 12*q^2 + 12*q^3 + 12*q^4 + 12*q^5 + 24*q^6 + 24*q^7 + 36*q^8 + 36*q^9 + O(q^10)
Return the ambient quaternion algebra that contains this fractional ideal.
OUTPUT: a quaternion algebra
EXAMPLES:
sage: I = BrandtModule(3,5).right_ideals()[1]; I
Fractional ideal (2 + 6*j + 4*k, 2*i + 4*j + 34*k, 8*j + 32*k, 40*k)
sage: I.quaternion_algebra()
Quaternion Algebra (-1, -3) with base ring Rational Field
Return the order for which this ideal is a left or right fractional ideal. If this ideal has both a left and right ideal structure, then the left order is returned. If it has neither structure, then an error is raised.
OUTPUT: QuaternionOrder
EXAMPLES:
sage: R = QuaternionAlgebra(-11,-1).maximal_order()
sage: R.unit_ideal().quaternion_order() is R
True
Return the right order associated to this fractional ideal.
OUTPUT: an order in a quaternion algebra
EXAMPLES:
sage: I = BrandtModule(389).right_ideals()[1]; I
Fractional ideal (2 + 6*j + 2*k, i + 2*j + k, 8*j, 8*k)
sage: I.right_order()
Order of Quaternion Algebra (-2, -389) with base ring Rational Field with basis (1/2 + 1/2*j + 1/2*k, 1/4*i + 1/2*j + 1/4*k, j, k)
sage: I.left_order()
Order of Quaternion Algebra (-2, -389) with base ring Rational Field with basis (1/2 + 1/2*j + 3/2*k, 1/8*i + 1/4*j + 9/8*k, j + k, 2*k)
The following is a big consistency check. We take reps for all the right ideal classes of a certain order, take the corresponding left orders, then take ideals in the left orders and from those compute the right order again:
sage: B = BrandtModule(11,19); R = B.right_ideals()
sage: O = [r.left_order() for r in R]
sage: J = [O[i].left_ideal(R[i].basis()) for i in range(len(R))]
sage: len(set(J))
18
sage: len(set([I.right_order() for I in J]))
1
sage: J[0].right_order() == B.order_of_level_N()
True
Return ring that this is a fractional ideal for.
EXAMPLES:
sage: R = QuaternionAlgebra(-11,-1).maximal_order()
sage: R.unit_ideal().ring() is R
True
Scale the fractional ideal self by multiplying the basis by alpha.
INPUT:
OUTPUT:
EXAMPLES:
sage: B = BrandtModule(5,37); I = B.right_ideals()[0]; i,j,k = B.quaternion_algebra().gens(); I
Fractional ideal (2 + 2*j + 106*k, i + 2*j + 105*k, 4*j + 64*k, 148*k)
sage: I.scale(i)
Fractional ideal [2*i + 212*j - 2*k, -2 + 210*j - 2*k, 128*j - 4*k, 296*j]
sage: I.scale(i, left=True)
Fractional ideal [2*i - 212*j + 2*k, -2 - 210*j + 2*k, -128*j + 4*k, -296*j]
sage: I.scale(i, left=False)
Fractional ideal [2*i + 212*j - 2*k, -2 + 210*j - 2*k, 128*j - 4*k, 296*j]
sage: i * I.gens()[0]
2*i - 212*j + 2*k
sage: I.gens()[0] * i
2*i + 212*j - 2*k
Return normalized theta series of self, as a power series over \(\ZZ\) in the variable var, which is ‘q’ by default.
The normalized theta series is by definition
INPUT:
OUTPUT: power series
EXAMPLES:
sage: I = BrandtModule(11).right_ideals()[1]; I
Fractional ideal (2 + 6*j + 4*k, 2*i + 4*j + 2*k, 8*j, 8*k)
sage: I.norm()
32
sage: I.theta_series(5)
1 + 12*q^2 + 12*q^3 + 12*q^4 + O(q^5)
sage: I.theta_series(5,'T')
1 + 12*T^2 + 12*T^3 + 12*T^4 + O(T^5)
sage: I.theta_series(3)
1 + 12*q^2 + O(q^3)
Return theta series coefficients of self, as a vector of B integers.
INPUT:
OUTPUT:
Vector over \(\ZZ\) with B entries.
EXAMPLES:
sage: I = BrandtModule(37).right_ideals()[1]; I
Fractional ideal (2 + 6*j + 2*k, i + 2*j + k, 8*j, 8*k)
sage: I.theta_series_vector(5)
(1, 0, 2, 2, 6)
sage: I.theta_series_vector(10)
(1, 0, 2, 2, 6, 4, 8, 6, 10, 10)
sage: I.theta_series_vector(5)
(1, 0, 2, 2, 6)
Bases: sage.rings.ring.Algebra
An order in a quaternion algebra.
EXAMPLES:
sage: QuaternionAlgebra(-1,-7).maximal_order()
Order of Quaternion Algebra (-1, -7) with base ring Rational Field with basis (1/2 + 1/2*j, 1/2*i + 1/2*k, j, k)
sage: type(QuaternionAlgebra(-1,-7).maximal_order())
<class 'sage.algebras.quatalg.quaternion_algebra.QuaternionOrder'>
Return fix choice of basis for this quaternion order.
EXAMPLES:
sage: QuaternionAlgebra(-11,-1).maximal_order().basis()
(1/2 + 1/2*i, 1/2*j - 1/2*k, i, -k)
Return the discriminant of this order, which we define as \(\sqrt{ det ( Tr(e_i \bar{e}_j ) ) }\), where \(\{e_i\}\) is the basis of the order.
OUTPUT: rational number
EXAMPLES:
sage: QuaternionAlgebra(-11,-1).maximal_order().discriminant()
11
sage: S = BrandtModule(11,5).order_of_level_N()
sage: S.discriminant()
55
sage: type(S.discriminant())
<type 'sage.rings.rational.Rational'>
Return the free \(\ZZ\)-module that corresponds to this order inside the vector space corresponding to the ambient quaternion algebra.
OUTPUT:
A free \(\ZZ\)-module of rank 4.
EXAMPLES:
sage: R = QuaternionAlgebra(-11,-1).maximal_order()
sage: R.basis()
(1/2 + 1/2*i, 1/2*j - 1/2*k, i, -k)
sage: R.free_module()
Free module of degree 4 and rank 4 over Integer Ring
Echelon basis matrix:
[1/2 1/2 0 0]
[ 0 1 0 0]
[ 0 0 1/2 1/2]
[ 0 0 0 1]
Return the n-th generator.
INPUT:
EXAMPLES:
sage: R = QuaternionAlgebra(-11,-1).maximal_order(); R
Order of Quaternion Algebra (-11, -1) with base ring Rational Field with basis (1/2 + 1/2*i, 1/2*j - 1/2*k, i, -k)
sage: R.gen(0)
1/2 + 1/2*i
sage: R.gen(1)
1/2*j - 1/2*k
sage: R.gen(2)
i
sage: R.gen(3)
-k
Return generators for self.
EXAMPLES:
sage: QuaternionAlgebra(-1,-7).maximal_order().gens()
(1/2 + 1/2*j, 1/2*i + 1/2*k, j, k)
Return the intersection of this order with other.
INPUT:
OUTPUT: a quaternion order
EXAMPLES:
sage: R = QuaternionAlgebra(-11,-1).maximal_order()
sage: R.intersection(R)
Order of Quaternion Algebra (-11, -1) with base ring Rational Field with basis (1/2 + 1/2*i, i, 1/2*j + 1/2*k, k)
We intersect various orders in the quaternion algebra ramified at 11:
sage: B = BrandtModule(11,3)
sage: R = B.maximal_order(); S = B.order_of_level_N()
sage: R.intersection(S)
Order of Quaternion Algebra (-1, -11) with base ring Rational Field with basis (1/2 + 1/2*j, 1/2*i + 5/2*k, j, 3*k)
sage: R.intersection(S) == S
True
sage: B = BrandtModule(11,5)
sage: T = B.order_of_level_N()
sage: S.intersection(T)
Order of Quaternion Algebra (-1, -11) with base ring Rational Field with basis (1/2 + 1/2*j, 1/2*i + 23/2*k, j, 15*k)
Return the ideal with given gens over \(\ZZ\).
INPUT:
EXAMPLES:
sage: R = QuaternionAlgebra(-11,-1).maximal_order()
sage: R.left_ideal([2*a for a in R.basis()])
Fractional ideal (1 + i, 2*i, j + k, 2*k)
Return the number of generators (which is 4).
EXAMPLES:
sage: QuaternionAlgebra(-1,-7).maximal_order().ngens()
4
Return the normalized quadratic form associated to this quaternion order.
OUTPUT: quadratic form
EXAMPLES:
sage: R = BrandtModule(11,13).order_of_level_N()
sage: Q = R.quadratic_form(); Q
Quadratic form in 4 variables over Rational Field with coefficients:
[ 14 253 55 286 ]
[ * 1455 506 3289 ]
[ * * 55 572 ]
[ * * * 1859 ]
sage: Q.theta_series(10)
1 + 2*q + 2*q^4 + 4*q^6 + 4*q^8 + 2*q^9 + O(q^10)
Return ambient quaternion algebra that contains this quaternion order.
EXAMPLES:
sage: QuaternionAlgebra(-11,-1).maximal_order().quaternion_algebra()
Quaternion Algebra (-11, -1) with base ring Rational Field
Return a random element of this order.
The args and kwds are passed to the random_element method of the integer ring, and we return an element of the form
where \(e_1\), ..., \(e_4\) are the basis of this order and \(a\), \(b\), \(c\), \(d\) are random integers.
EXAMPLES:
sage: QuaternionAlgebra(-11,-1).maximal_order().random_element()
-4 - 4*i + j - k
sage: QuaternionAlgebra(-11,-1).maximal_order().random_element(-10,10)
-9/2 - 7/2*i - 7/2*j - 3/2*k
Return the ideal with given gens over \(\ZZ\).
INPUT:
EXAMPLES:
sage: R = QuaternionAlgebra(-11,-1).maximal_order()
sage: R.right_ideal([2*a for a in R.basis()])
Fractional ideal (1 + i, 2*i, j + k, 2*k)
Return the ternary quadratic form associated to this order.
INPUT:
OUTPUT:
This function computes the positive definition quadratic form obtained by letting G be the trace zero subspace of \(\ZZ\) + 2* self, which has rank 3, and restricting the pairing:
(x,y) = (x.conjugate()*y).reduced_trace()
to \(G\).
APPLICATIONS: Ternary quadratic forms associated to an order in a rational quaternion algebra are useful in computing with Gross points, in decided whether quaternion orders have embeddings from orders in quadratic imaginary fields, and in computing elements of the Kohnen plus subspace of modular forms of weight 3/2.
EXAMPLES:
sage: R = BrandtModule(11,13).order_of_level_N()
sage: Q = R.ternary_quadratic_form(); Q
Quadratic form in 3 variables over Rational Field with coefficients:
[ 5820 1012 13156 ]
[ * 55 1144 ]
[ * * 7436 ]
sage: factor(Q.disc())
2^4 * 11^2 * 13^2
The following theta series is a modular form of weight 3/2 and level 4*11*13:
sage: Q.theta_series(100)
1 + 2*q^23 + 2*q^55 + 2*q^56 + 2*q^75 + 4*q^92 + O(q^100)
Return the unit ideal in this quaternion order.
EXAMPLES:
sage: R = QuaternionAlgebra(-11,-1).maximal_order()
sage: I = R.unit_ideal(); I
Fractional ideal (1/2 + 1/2*i, 1/2*j - 1/2*k, i, -k)
Return a basis for the \(\ZZ\)-lattice in a quaternion algebra spanned by the given gens.
INPUT:
EXAMPLES:
sage: from sage.algebras.quatalg.quaternion_algebra import basis_for_quaternion_lattice
sage: A.<i,j,k> = QuaternionAlgebra(-1,-7)
sage: basis_for_quaternion_lattice([i+j, i-j, 2*k, A(1/3)])
[1/3, i + j, 2*j, 2*k]
sage: basis_for_quaternion_lattice([A(1),i,j,k])
[1, i, j, k]
Intersects the \(\ZZ\)-modules with basis matrices the full rank \(4 \times 4\) \(\QQ\)-matrices in the list v. The returned intersection is represented by a \(4 \times 4\) matrix over \(\QQ\). This can also be done using modules and intersection, but that would take over twice as long because of overhead, hence this function.
EXAMPLES:
sage: a = matrix(QQ,4,[-2, 0, 0, 0, 0, -1, -1, 1, 2, -1/2, 0, 0, 1, 1, -1, 0])
sage: b = matrix(QQ,4,[0, -1/2, 0, -1/2, 2, 1/2, -1, -1/2, 1, 2, 1, -2, 0, -1/2, -2, 0])
sage: c = matrix(QQ,4,[0, 1, 0, -1/2, 0, 0, 2, 2, 0, -1/2, 1/2, -1, 1, -1, -1/2, 0])
sage: v = [a,b,c]
sage: from sage.algebras.quatalg.quaternion_algebra import intersection_of_row_modules_over_ZZ
sage: M = intersection_of_row_modules_over_ZZ(v); M
[ -2 0 1 1]
[ -4 1 1 -3]
[ -3 19/2 -1 -4]
[ 2 -3 -8 4]
sage: M2 = a.row_module(ZZ).intersection(b.row_module(ZZ)).intersection(c.row_module(ZZ))
sage: M.row_module(ZZ) == M2
True
Return True if A is of the QuaternionAlgebra data type.
EXAMPLES:
sage: sage.algebras.quatalg.quaternion_algebra.is_QuaternionAlgebra(QuaternionAlgebra(QQ,-1,-1))
True
sage: sage.algebras.quatalg.quaternion_algebra.is_QuaternionAlgebra(ZZ)
False
Given a and b and an even prime ideal p find (y,z,w) with y a unit mod \(p^{2e}\) such that
where \(e\) is the ramification index of \(p\).
Currently only \(p=2\) is implemented by hardcoding solutions.
INPUT:
OUTPUT:
EXAMPLES:
sage: from sage.algebras.quatalg.quaternion_algebra import maxord_solve_aux_eq
sage: for a in [1,3]:
....: for b in [1,2,3]:
....: (y,z,w) = maxord_solve_aux_eq(a, b, 2)
....: assert mod(y, 4) == 1 or mod(y, 4) == 3
....: assert mod(1 - a*y^2 - b*z^2 + a*b*w^2, 4) == 0
Computes a (at p) normalized basis from the given basis e of a \(\ZZ\)-module.
The returned basis is (at p) a \(\ZZ_p\) basis for the same module, and has the property that with respect to it the quadratic form induced by the bilinear form B is represented as a orthogonal sum of atomic forms multiplied by p-powers.
If \(p \neq 2\) this means that the form is diagonal with respect to this basis.
If \(p = 2\) there may be additional 2-dimensional subspaces on which the form is represented as \(2^e (ax^2 + bxy + cx^2)\) with \(0 = v_2(b) = v_2(a) \leq v_2(c)\).
OUTPUT:
EXAMPLES:
sage: from sage.algebras.quatalg.quaternion_algebra import normalize_basis_at_p
sage: A.<i,j,k> = QuaternionAlgebra(-1, -1)
sage: e = [A(1), i, j, k]
sage: normalize_basis_at_p(e, 2)
[(1, 0), (i, 0), (j, 0), (k, 0)]
sage: A.<i,j,k> = QuaternionAlgebra(210)
sage: e = [A(1), i, j, k]
sage: normalize_basis_at_p(e, 2)
[(1, 0), (i, 1), (j, 1), (k, 2)]
sage: A.<i,j,k> = QuaternionAlgebra(286)
sage: e = [A(1), k, 1/2*j + 1/2*k, 1/2 + 1/2*i + 1/2*k]
sage: normalize_basis_at_p(e, 5)
[(1, 0), (1/2*j + 1/2*k, 0), (-5/6*j + 1/6*k, 1), (1/2*i, 1)]
sage: A.<i,j,k> = QuaternionAlgebra(-1,-7)
sage: e = [A(1), k, j, 1/2 + 1/2*i + 1/2*j + 1/2*k]
sage: normalize_basis_at_p(e, 2)
[(1, 0), (1/2 + 1/2*i + 1/2*j + 1/2*k, 0), (-34/105*i - 463/735*j + 71/105*k, 1), (-34/105*i - 463/735*j + 71/105*k, 1)]
The 0th version of pickling for quaternion algebras.
EXAMPLES:
sage: Q = QuaternionAlgebra(-5,-19)
sage: t = (QQ, -5, -19, ('i', 'j', 'k'))
sage: sage.algebras.quatalg.quaternion_algebra.unpickle_QuaternionAlgebra_v0(*t)
Quaternion Algebra (-5, -19) with base ring Rational Field
sage: loads(dumps(Q)) == Q
True
sage: loads(dumps(Q)) is Q
True